Solve the following linear equations
Ejercicio 1
\[(2x + 5) = ( x - 1 ) + 2\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 2
\[- (4x + 1) = ( x + 4 ) + 5\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 3
\[(-x + 4) = - ( 4x + 6 ) - 8\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 4
\[2 ( 3x + 3 ) = -2 ( x + 2 ) - 22\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 5
\[-3 ( 5x + 3 ) = 4 ( 5x + 6 ) + 37\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 6
\[-4 ( x + 4 ) = 6 ( 4x - 2 ) - 32\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 7
\[\frac{4}{3} ( \frac{3}{5}x + \frac{3}{5} ) = \frac{-4}{3} ( \frac{-3}{2}x + 1 ) + \frac{77}{15}\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 8
\[\frac{-4}{5} ( \frac{1}{5}x + \frac{4}{5} ) = \frac{2}{3} ( 3x + \frac{1}{2} ) - \frac{389}{150}\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
Ejercicio 9
\[-4 ( -2x + \frac{4}{5} ) = -1 ( x + 1 ) + \frac{16}{5}\]
\[x = \mathbf{?}\]
\[x = \mathbf{?}\]
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